From: Eliezer S. Yudkowsky (sentience@pobox.com)
Date: Wed Apr 30 2003 - 13:25:49 MDT
Rafal Smigrodzki wrote:
>>
>>Here's another trick question that only the true Bayesian will
>>resolve. You meet a mathematician. "How many children do you have?"
>>you ask. "Two," he replies, "and at least one of them is a boy."
>>What is the probability that they are both boys?
>>
>>I would *not* answer 1/3.
>
> 1/2 ?
That's one defensible answer for a Bayesian.
The classic form of the brainteaser runs as follows. You meet a
mathematician, who says he has two children. You ask "Is at least one of
your children a boy?" and the mathematician answers yes. In this case, of
course, the chance that the remaining child is a girl is 2/3.
If you meet a mathematician who just happens to remark "At least one of my
children is a boy", it is obvious that he is trying to pose the above
brainteaser. We can suppose a prior 1/4 chance that he has two boys, a
prior 1/4 chance that he has two girls, and a 1/2 chance that he has a
boy-girl or girl-boy pair. If he has two boys, he must pose the
brainteaser by saying "At least one of my children is a boy." If he has
two girls, he must pose the brainteaser by saying "At least one of my
children is a girl." We suppose that if he has a mixed pair, he is
equally likely to pose the question one way or the other. If the
mathematician says "At least one of my children is a boy", the
probabilities to consider are p(.25)*p(1) and p(.50)*p(.50). So it is
equally probable that the mathematician's other child is a boy or a girl.
But if I encountered this situation in real life, I'd guess around an 80%
chance that the mathematician had a mixed pair. Why? Because the
mathematician knows that the mixed pair is the "correct" answer, and would
be less likely to choose this problem as a good illustration if that were
not actually the case...
-- Eliezer S. Yudkowsky http://singinst.org/ Research Fellow, Singularity Institute for Artificial Intelligence
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