This all brings up the question... if you want to survive the longest,
all else being equal, where do you choose to live in the year 2000?
Dana Hedberg wrote:
>
> > According to my math, this is:
> >
> > 381 / 82.087.361 = 4,6414E-06 = 0,00046%
> > 12.448 / 272.639.608 = 4,56573E-05 = 0,00457%
> >
> > This is roughly ten times the number of murders per population. I apologize
> > for not including this figure. But it should be obvious that there is a huge
> > difference between the kills/population ratio here and in the US. The
> > logical question now would be why we have this difference.
> >
> > The number of murders in the US is from 1998 because the FBI did not publish
> > the final report for 1999 on the Internet up to now.
> >
> > Karsten
>
> I would be curious to see these numbers as a function of population
> density and perhaps controlling for SES. My hypothesis would be that
> areas with a high population density have the highest murder rate. A
> corollary to that would be, highly dense areas with low SES (but
> probably not starvation level) have the highest rate of murder with a
> gun being the weapon of choice most likely irrespective of that areas
> gun laws.
>
> I'm sure there has been some studies done looking at these factors.
> Mike, you have anything handy?
>
> -Dana
This archive was generated by hypermail 2b29 : Thu Jul 27 2000 - 14:13:59 MDT