Re: Black hole question

From: Spike Jones (spike66@ibm.net)
Date: Tue Feb 15 2000 - 21:08:54 MST


> "Stirling Westrup" <sti@cam.org> writes:
>
> ...One is that the final resulting black hole has an apparant volume less than the
> sum of the apparant volumes of the two colliding holes.
>
> [Anders Sandberg has] learned it
> prevents me from travelling through the central hole in a large
> artificial doughnut-shaped black hole - it collapses faster than I can
> travel through it... :-)

I dont grok this. The mass of the combined black holes would be twice
the mass of the two original ones, and since the radius of the event horizon
is proportional to the mass, then the combined mass would have twice the
radius and thus eight times the apparent volume as the original two. Does
it not work that way? spike



This archive was generated by hypermail 2b29 : Thu Jul 27 2000 - 14:03:48 MDT