From: Adrian Tymes (wingcat@pacbell.net)
Date: Wed Apr 16 2003 - 22:58:41 MDT
--- Ramez Naam <mez@apexnano.com> wrote:
> For example, consider the following entirely
> theoretical scenario:
>
> 1) Humans who possess allele A1 of gene A have a
> normal distribution
> of IQ relative to the general population.
>
> 2) Humans who possess allele B1 of gene B have a
> normal distribution
> of IQ relative to the general population.
>
> 3) Humans who possess BOTH A1 and B1 have a
> statistically significant
> increase in their average IQ relative to the general
> population.
>
> So I want to be able to determine the number of
> humans whose genotype
> and phenotype we'd have to capture in order to find
> this effect.
Basic probability. Say P(X) is the probability that
some random person has X. So, in this case,
P(A1)*P(B1)
is the probability that someone has both A1 and B1,
assuming A1 and B1 are not correlated at all. Of
course, if the combination of A1 and B1 confers some
survival and reproductive advantage - like, say,
conferring higher IQ - then the probability of the
combination will be greater than the product of their
individual probabilities; specifically, P(A1&B1) will
be somewhere between P(A1)*P(B1) and the lower of
P(A1)
and P(B1).
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