Lee Corbin wrote:
> equations "ab - cd = 1" or "a^2 + b^2 = c^2 + 1". I worry
> that the first may not even be possible---
Oh by the way, ab - cd = 1 also has infinitely many solutions:
where a = b and c = a-1 and d = a+1, a,b,c,d all integers, then
ab - cd = a^2 - (a-1)(a+1)= a^2 - (a^2 -1) = 1.
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