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*> > > "a^2 + b^2 = c^2 + 1".
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*> >
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*> spike Jones wrote: > By inspection this has infinitely many solutions.
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Dan Fabulich wrote:

*> But *which* solutions? Can you come up with a function for a, b and c
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*> such that they'll always satisfy this equation?
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Sure: a = +/-1, b = +/- c,

or: b = +/-1, a = +/- c

Here are some examples of solutions to a^2 + b^2 = c^2 + 1:

a b c

1 2 -2

-1 -3 3

4 -1 - 4

-1 5 -5

-6 1 6

1 7 7

+/-1 +/-n +/-n

+/-n +/-1 +/-n

where n is any integer.

*> That's what's meant by a "solution" here.
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Dan, perhaps Ive misunderstood the question? spike

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